I'm not sure if the MiG-31 and 25's vertical stabilizers can be described as "canted."
They appear to be canted to me in the perspective view pictures in press releases. The F-15 vertical stabilizers are actually vertical.
They look too close to the vertical when compared to the F-117, F-18, F-22 and the recent Iranian abomination of the F-5. Those had really canted vertical stabilizers.
They're oriented more vertically than the fighters you mentioned, I agree. But they were also fairly large for directional stability at very high altitude flight. That would go for many fighters that can intercept at, say, 60,000'+
As far as I know, the F-15SE is still rated as a Mach 2.2 fighter or at best Mach 2.5 at altitude. Unlikely that it will achieve 3.0 Mach without some kinda descent.
I can try and do that math on that, so for starters:
Basic aerodynamic lift =
V^2 * rho * C(sub)l * S/2
where,
V^2 = forward air velocity in ft/sec squared
rho = air density in 'slugs/cubic ft' at any altitude
C(sub)l = Co-efficient of lift, a small decimal number, usually less than .03 subsonically
S/2 = wing area in sq/ft divided by 2
Now, for the horsepower required to maintain altitude:
Look at the heading 'B.' in this:
UNIFIED PROPULSION 4
My Dad hand-wrote a re-arranged version of the equation in his college textbook margin, but I admit I can't find the book since I moved last. So, here it is from memory:
....... _____________________
...... / ....available (jet gas) HP * 1100
...3 / .....-----------------------------------
....\/ .............C(sub)d * S * V^2
where,
V^2 = the same as above
C(sub)d = Co-efficient of drag
S = wing area as such in Sq. ft.
(Jet gas) HP = Total thrust reacting on the airframe at altitude, times 1100
to determine
available HP,
take the forward velocity, divide by 550 and multiply that by available thrust
thus,
(Velocity in ft/sec / 550) * lbs available thrust = available HP
Everything above has the cube root taken of it for the maximum speed at a given altitude.
What I need to do next is research the thrust available at M2.5 an about 50,000-70,000 ft. There were research papers written by undergraduate university students for the annual AIAA aircraft design competition. The information for theoretical interceptors and bombers is there in the 'Web to be abstracted from unclassified data in the paper(s).
I'll do that over the weekend.
Finally,
From what I understand, jet engines also have difficulty making Mach 3.0 as the engines themselves become a source of drag.
They do, yes. But in the case of the J-58 engine of the SR-71, air from the last compressor stage was piped back to the afterburner, thus reducing SFC by---I've read---about 2%. There is a partial way around that.
REEDIT:
Now I have the 'Web references for standard atmospheric rho and another one for a scalable engine performance estimation.
Rho by 1,000 ft intervals to 28K and 2,000 ft intervals to 100k ft:
http://cobweb.ecn.perdue.edu/propulsi/propulsion/flow/stdatm.html
and,
A research paper from Calpoly's aerospace undergraduate program
The Vendetta---Preliminary Design Report
GOOGLize:
"vendetta bomber pdf" --- the first or second hit should be the paper in question.
(There's a substitution in the browser address for Firefox that makes the original address indecipherable.) Google will have to do. Software, you know. I can look for another site that gives a direct 'Web address for downloading.